Cart

Your cart is empty

⭐️⭐️⭐️⭐️⭐️ Our sustainable cashmere has thousands of 5-star reviews

Brand New Givenchy Monochrome Silk Scarf

£295.00

Immaculate condition with an elegant and timeless design from this luxury French fashion house. Beautiful silk twill with hand rolled edges. Brand new without tags. Made in Italy and measuring 35 inches square.

Easy returns & free UK shipping over £75

Brand New Givenchy Monochrome Silk Scarf

£295.00

#1

Immaculate second hand cashmere, keeping you warm without costing the Earth..

#2

The UK's largest selection of second hand cashmere.

#3

Breathing new life into over 30,000 cashmere jumpers every year.

Meet the founder

Free delivery when you spend £75

and free returns when you exchange!

Immaculate Second hand cashmere

Keeping you warm without costing the Earth.

The UK's largest selection of second hand cashmere

There's something for everyone.

A small family business you can trust

We pride ourselves on our customer service.

document.addEventListener("DOMContentLoaded", function () { if (document.body.classList.contains('collection-women')) { const container = document.querySelector('[data-id="main-collection-product-grid"], .product-grid, .grid, .collection__products'); // Try all common selectors if (!container) return; const items = Array.from(container.children); // Fisher-Yates shuffle for (let i = items.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [items[i], items[j]] = [items[j], items[i]]; } // Re-append in new order items.forEach(item => container.appendChild(item)); } }); document.addEventListener("DOMContentLoaded", function () { if (document.body.classList.contains('collection-women')) { const container = document.querySelector('[data-id="main-collection-product-grid"], .product-grid, .grid, .collection__products'); // Try all common selectors if (!container) return; const items = Array.from(container.children); // Fisher-Yates shuffle for (let i = items.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [items[i], items[j]] = [items[j], items[i]]; } // Re-append in new order items.forEach(item => container.appendChild(item)); } });